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9 points
by
curi
6159 days ago |
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why not change x!y to x.'y ? seems a bit easier to remember, saves ! for something else. dunno if there's a parsing problem with it.
7 points
by
pg
6159 days ago |
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Hmm, never thought of that. I'll consider it.
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3 points
by
mattjones
6159 days ago |
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What if x.y!z expanded to ((x y) z)? Then if x were '(1 2 (3 4) 5), x.2!1 would give you 4. If (x 1 3) did work like cut, then you could do x.1.3!1!1, which would also give 4 in this case.
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