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2 points
by
Jesin
6142 days ago |
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I wonder how we would deal with this:
[(foo _ _) baz _]
Does that mean
(fn (x) ((foo x x) baz x))
or does it mean
(fn (x) ((fn (y) (fn (z) (foo y z))) baz x))
1 point
by
cchooper
6142 days ago |
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It would mean the former. I think that's the only sensible way to do it.
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